void printBoard(Game& game) { cout << " A B C D E F G H\n\n"; for (int iLine = 7; iLine >= 0; iLine--) { if ( iLine%2 == 0) { // Line starting with BLACK printLine(iLine, BLACK_SQUARE, WHITE_SQUARE, game); } else { // Line starting with WHITE printLine(iLine, WHITE_SQUARE, BLACK_SQUARE, game); } } } void printLine(int iLine, int iColor1, int iColor2, Game& game) { // Define the CELL variable here. // It represents how many horizontal characters will form one squarite // The number of vertical characters will be CELL/2 // You can change it to alter the size of the board // (an odd number will make the squares look rectangular) int CELL = 6; // Since the width of the characters BLACK and WHITE is half of the height, // we need to use two characters in a row. // So if we have CELL characters, we must have CELL/2 sublines for (int subLine = 0; subLine < CELL/2; subLine++) { // A sub-line is consisted of 8 cells, but we can group it // in 4 iPairs of black&white for (int iPair = 0; iPair < 4; iPair++) { // First cell of the pair for (int subColumn = 0; subColumn < CELL; subColumn++) { // The piece should be in the "middle" of the cell // For 3 sub-lines, in sub-line 1 // For 6 sub-columns, sub-column 3 if ( subLine == 1 && subColumn == 3) { cout << char(game.getPieceAtPosition(iLine, iPair*2) != 0x20 ? game.getPieceAtPosition(iLine, iPair*2) : iColor1); } else { cout << char(iColor1); } } // Second cell of the pair for (int subColumn = 0; subColumn < CELL; subColumn++) { // The piece should be in the "middle" of the cell // For 3 sub-lines, in sub-line 1 // For 6 sub-columns, sub-column 3 if ( subLine == 1 && subColumn == 3) { cout << char(game.getPieceAtPosition(iLine,iPair*2+1) != 0x20 ? game.getPieceAtPosition(iLine,iPair*2+1) : iColor2); } else { cout << char(iColor2); } } } } }